From kehld@ktk.pte.hu Tue May 25 16:41:56 2010
From: Kehl D =?utf-8?q?=C3=A1niel?= <kehld@ktk.pte.hu>
To: gretl-users@gretlml.univpm.it
Subject: Re: [Gretl-users] Loop question
Date: Tue, 25 May 2010 22:41:55 +0200
Message-ID: <1274820115.864b159ckehld@ktk.pte.hu>
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Dear Henrique,

you have to simply follow the syntax. Take a look at Chapter 9 in the User's =
Guide (Help/User's guide in the menu). Simple example on page 60 will help!

Best wishes
Daniel

-----Original Message-----
From: Henrique Andrade <henrique.coelho(a)gmail.com>
To: Gretl list <gretl-users(a)lists.wfu.edu>
Date: Tue, 25 May 2010 16:53:54 -0300
Subject: Re: [Gretl-users] Loop question

Dear Riccardo, Kehl and Artur,

Thanks a lot for your help! I'd tried all the options you gave me and
my final script looks like this:

<script>
scalar n=3D0
loop for (n=3D6;n<=3D24;n=3Dn*2) --quiet
    scalar m =3D $T - n + 1
    loop j=3D2..nelemY --quiet
        matrix R$n_$j =3D zeros(m,1)
        loop i=3D1..m --quiet
            loop c=3D1..n --quiet
                row =3D i + n - c
                R$n_$j[i] +=3D r$j[row, c]
            endloop
        endloop
    endloop
    matrix mci$n =3D R$n_2 + R$n_3
endloop
</script>

Now, because I just need the values for 6, 12 and 24, I'm trying to
substitute the second line "loop for (n=3D6;n<=3D24;n=3Dn*2)" for this:

loop for (n=3D6;n=3D12;n=3D24)

But the script isn't working. Any hints?

Best regards,
Henrique


2010/5/25 artur bala <artur.bala(a)laposte.net>

> Or, if your index is something like of a geometric series as it seems to
> be (let's say 6, 12, 24, 48, and so on) and too long to do manually
> you can try this one:
> <script>
> scalar count=3D0
> loop for (count=3D6;count<=3D24;count=3Dcount*2) --quiet
>    <instructions>
> endloop
> <\script>
>
> cheers,
> artur
>
> Riccardo (Jack) Lucchetti a =C3=A9crit :
> > On Tue, 25 May 2010, Henrique Andrade wrote:
> >
> >> Dear Gretl Community,
> >>
> >> I'm trying to use a loop index inside a script but I don't know how.
> >> According
> >> to "Gretl User=E2=80=99s Guide" the syntax looks like this:
> >>
> >> loop i=3D1..24
> >>
> >> But I just need the points where "i" is equal to 6, 12 and 24.
> >> Something like this:
> >>
> >> loop i=3D6;12;24
> >>
> >> How can I do that?
> >
> > For example, this way:
> > <script>
> > matrix foo =3D { 6, 12, 24 }
> > n =3D cols(foo)
> > loop for i=3D1..n
> >     bar =3D foo[i]
> >     print bar
> > end loop
> > </script>
> >
> >
> > Riccardo (Jack) Lucchetti
> > Dipartimento di Economia
> > Universit=C3=A0 Politecnica delle Marche
> >
> > r.lucchetti(a)univpm.it
> > http://www.econ.univpm.it/lucchetti
> > ------------------------------------------------------------------------
> >
> > _______________________________________________
> > Gretl-users mailing list
> > Gretl-users(a)lists.wfu.edu
> > http://lists.wfu.edu/mailman/listinfo/gretl-users
>
>
> _______________________________________________
> Gretl-users mailing list
> Gretl-users(a)lists.wfu.edu
> http://lists.wfu.edu/mailman/listinfo/gretl-users
>



--=20
Henrique C. de Andrade
Doutorando em Economia Aplicada
Universidade Federal do Rio Grande do Sul
www.ufrgs.br/ppge





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