From artur.bala@laposte.net Tue May 25 13:38:17 2010
From: artur bala <artur.bala@laposte.net>
To: gretl-users@gretlml.univpm.it
Subject: Re: [Gretl-users] Loop question
Date: Tue, 25 May 2010 18:38:10 +0100
Message-ID: <4BFC0B02.4040300@laposte.net>
In-Reply-To: alpine.DEB.2.00.1005250806090.7497@ec-4.econ.univpm.it
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Or, if your index is something like of a geometric series as it seems to 
be (let's say 6, 12, 24, 48, and so on) and too long to do manually
you can try this one:
<script>
scalar count=0
loop for (count=6;count<=24;count=count*2) --quiet
    <instructions>
endloop
<\script>

cheers,
artur

Riccardo (Jack) Lucchetti a écrit :
> On Tue, 25 May 2010, Henrique Andrade wrote:
>
>> Dear Gretl Community,
>>
>> I'm trying to use a loop index inside a script but I don't know how. 
>> According
>> to "Gretl User’s Guide" the syntax looks like this:
>>
>> loop i=1..24
>>
>> But I just need the points where "i" is equal to 6, 12 and 24. 
>> Something like this:
>>
>> loop i=6;12;24
>>
>> How can I do that?
>
> For example, this way:
> <script>
> matrix foo = { 6, 12, 24 }
> n = cols(foo)
> loop for i=1..n
>     bar = foo[i]
>     print bar
> end loop
> </script>
>
>
> Riccardo (Jack) Lucchetti
> Dipartimento di Economia
> Università Politecnica delle Marche
>
> r.lucchetti(a)univpm.it
> http://www.econ.univpm.it/lucchetti
> ------------------------------------------------------------------------
>
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> Gretl-users mailing list
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