Hello,

I'm trying to have a rapid way to output numbers to files, and wrote the
following:


# A function to dump numbers to files:
function scalar to_file(scalar numb, string format, string filename)
    set echo off
    set messages off
    outfile filename --write
    printf format, numb
    outfile --close
    set echo on
    set messages on
    return 0
end function


which however doesn't work. By trying different specifications, I think
I have understood that the "filename" parameter of "outfile" and the
"format" parameter of "printf" cannot be variables, they are parsed
directly as strings by the interpreter.

Did I understand correctly?
Is there anything I can do to solve my problem?

I do not care too much, in the end, about "format", but if there is no
way to pass an arbitraray string to "outfile" I'm clearly trying
something stupid.

Thanks in advance

Pietro

your function should work. (not tested)

-- 
Ignacio Diaz-Emparanza 
DEPARTAMENTO DE ECONOMÍA APLICADA III (ECONOMETRÍA Y ESTADÍSTICA) 
UPV/EHU Avda. Lehendakari Aguirre, 83 | 48015 BILBAO 
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