On Thu, 15 Nov 2012, Pindar wrote:

And in terms of 'the loop line' string-substitution generates also an error:
(my challenge solution of the interaction stuff)

True, up till now $-string substitution has not been available 
in the line that starts a loop. This is now relaxed. In 
current CVS both of the following should work OK, regardless 
of the language in which gretl is running:

<hansl>
# Using numerical values
loop i=1..4 -q
   printf "i=%d\n", i
   loop j=i+1..i+2 -q
     printf "  j=%d\n", j
   endloop
endloop

# Using string substitution
loop i=1..4 -q
   printf "i=$i\n"
   loop j=$i+1..$i+2 -q
     printf "  j=$j\n"
   endloop
endloop
</hansl>

Allin Cottrell
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