Dear Riccardo, Kehl and Artur,
Thanks a lot for your help! I'd tried all the options you gave me and
my final script looks like this:
<script>
scalar n=0
loop for (n=6;n<=24;n=n*2) --quiet
scalar m = $T - n + 1
loop j=2..nelemY --quiet
matrix R$n_$j = zeros(m,1)
loop i=1..m --quiet
loop c=1..n --quiet
row = i + n - c
R$n_$j[i] += r$j[row, c]
endloop
endloop
endloop
matrix mci$n = R$n_2 + R$n_3
endloop
</script>
Now, because I just need the values for 6, 12 and 24, I'm trying to
substitute the second line "loop for (n=6;n<=24;n=n*2)" for this:
loop for (n=6;n=12;n=24)
But the script isn't working. Any hints?
Best regards,
Henrique
Or, if your index is something like of a geometric series as it seems to
be (let's say 6, 12, 24, 48, and so on) and too long to do manually
you can try this one:
<script>
scalar count=0
loop for (count=6;count<=24;count=count*2) --quiet
<instructions>
endloop
<\script>
cheers,
artur
Riccardo (Jack) Lucchetti a écrit :
> ------------------------------------------------------------------------> On Tue, 25 May 2010, Henrique Andrade wrote:
>
>> Dear Gretl Community,
>>
>> I'm trying to use a loop index inside a script but I don't know how.
>> According
>> to "Gretl User’s Guide" the syntax looks like this:
>>
>> loop i=1..24
>>
>> But I just need the points where "i" is equal to 6, 12 and 24.
>> Something like this:
>>
>> loop i=6;12;24
>>
>> How can I do that?
>
> For example, this way:
> <script>
> matrix foo = { 6, 12, 24 }
> n = cols(foo)
> loop for i=1..n
> bar = foo[i]
> print bar
> end loop
> </script>
>
>
> Riccardo (Jack) Lucchetti
> Dipartimento di Economia
> Università Politecnica delle Marche
>
> r.lucchetti@univpm.it
> http://www.econ.univpm.it/lucchetti
>
> _______________________________________________
> Gretl-users mailing list
> Gretl-users@lists.wfu.edu
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