On Thu, 25 Jul 2013, Logan Kelly wrote:
 I have two questions. First, is this the correct list to 
 post this question? I am not sure if it belongs here or in 
 the gretl-devl list. Apologies, if I have guessed wrongly. 
Could go either way, no worries.
 Second, regarding accessing a list element. Should following 
 assign the data in the first series of lstX to matrix matX?
 matrix matX = {lstX[1]}
 Currently, this yields the matX = series id number. This 
 question is related to an earlier question on the list see 
 below. 
That's what I'd expect. A named list in gretl is an array of 
ID numbers of series in the current dataset. Let's look at the 
related case you mention:
>> Is it possible to access elements of a list. I need the
variable name-as a
>> string-of the i_th element of a list. Something like
>>
>> string variable_name = varnam(ylist[i])
>
> You can't directly index into a list [...]
 Actually, that seems a bit lame. Now in CVS and snapshots you
 can do that -- the expression above should now work (apart
 from the typo of "varnam" for "varname" ;-). 
The help doc says of the varname() function: "If given an 
integer argument [v], returns the name of the variable with ID 
number v, or generates an error if there is no such variable." 
The expression "ylist[i]", for ylist a named list and i an 
index within bounds for the list, yields a particular series 
ID number, which is what's wanted as an argument for 
varname().
A series ID number can be used as such in many contexts in 
gretl (mostly commands rather than functions), but if you try 
to use it in creating a matrix, as in
matrix matX = {lstX[1]}
the interpretation of the "ID number" as simply a number 
trumps its interpretation as the index of a series -- 
otherwise it would be impossible to construct a plain 
numerical matrix as, say,
matrix m = {1,2,3}
So: you can (now) index into a list using listname[i], but 
this gives you an integer result, which will be interpreted as 
a series index only in certain contexts (which should all be 
identified as such in the command and function help, I 
believe).
Allin Cottrell