Am 13.08.2020 um 08:50 schrieb Jan Annaert:
On 12/08/2020, 23:45, "Sven Schreiber"
<svetosch(a)gmx.net> wrote:
Am 12.08.2020 um 19:12 schrieb Alecos Papadopoulos:
> Why is this happening, considering that X^(1/3) is a real number even if
> X is a negative number?
Good question. I'm noticing that 'eval -1^(1/3)' works fine, in
contrast.
--> I guess that's because exponentiation takes precedence over negation.
'eval (-1)^(1/3)' results in NaN.
Of course you're right!
thanks
sven