Re: [Gretl-users] loop, string substitution and varname from list
Am 23.02.2017 um 15:50 schrieb Schaff, Frederik:
Many thanks to both of you! The second, more general is working
fine.
Although it would be a nice feature if one could directly access the
name of a variable (something like idname).
For a list L, "(varnames(L))[i]" should get you a string with the name
of the i-th variable in the list.
(Allin, if you read this: "varnames(L)[i]" produces an error, the extra
parenthesis is necessary, don't know whether that's a bug, although I
certainly understand why gretl is choking.)
cheers,
sven