As far as I know in Case 1 phor is an index variable that starts at one and is incremented by one for each next string in the list of strings. In the example there are three strings in the list ("0", "1" and "2"), so phor takes the values 1, 2 and 3. In case 2, phor is a scalar that starts at 0 and is incremented until it eventually reaches 2, so it takes the values 0, 1 and 2. So, no the results are not identical. Best regards, Jan Annaert From: Henrique Andrade <henrique.coelho@gmail.com<mailto:henrique.coelho@gmail.com>> Reply-To: "gretl-users@lists.wfu.edu<mailto:gretl-users@lists.wfu.edu>" <gretl-users@lists.wfu.edu<mailto:gretl-users@lists.wfu.edu>> Date: maandag 22 oktober 2012 16:36 To: "gretl-users@lists.wfu.edu<mailto:gretl-users@lists.wfu.edu>" <gretl-users@lists.wfu.edu<mailto:gretl-users@lists.wfu.edu>> Subject: [Gretl-users] The Loop Mystery (differences between "loop" and "loop foreach") Dear Gretl Community, I would like to know what is wrong in the following loops (Case 1 and Case 2): # Case 1 loop foreach phor 0 1 2 --quiet loop i = 1..2 --quiet loop j = phor+1..phor+2 --quiet scalar TESTE = $j print TESTE endloop endloop endloop # Case 2 loop phor = 0..2 --quiet loop i = 1..2 --quiet loop j = phor+1..phor+2 --quiet scalar TESTE = $j print TESTE endloop endloop endloop As much as I know, they should present the same result. Am I wrong? Best regards, Henrique Andrade