Ehm... Probably I have used extra (and non necessary) commands!!!
but I got the result :)
here is the code...
i=1
scalar D= abs(IP[i,])
loop 60
if D < abs(IP[i+1,])
D = abs(IP[i+1,])
else
D=D
endif
i=i+1
endloop
so, you are saying that i can simply put
D = max(abs(IP)) ??
im my data IP is saved as a matrix (60x1)...
2013/6/17 Sven Schreiber <svetosch(a)gmx.net>
Am 17.06.2013 12:03, schrieb Gabriela Nodari:
> the supremum of a time series: Oh right, I got it with a simple loop...
>
>
huh?? What about max()? Granted, it's "only" the maximum, but computers
never find suprema...
-s
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Ehm... Probably I have used extra (and non necessary) commands!!!
but I got the result :)
here is the code...
i=1
scalar D= abs(IP[i,])
loop 60
if D < abs(IP[i+1,])
D = abs(IP[i+1,])
else
D=D
endif
i=i+1
endloop
so, you are saying that i can simply put
D = max(abs(IP)) ??
im my data IP is saved as a matrix (60x1)...
2013/6/17 Sven Schreiber <svetosch(a)gmx.net>
> Am 17.06.2013 12:03, schrieb Gabriela Nodari:
> > the supremum of a time series: Oh right, I got it with a simple loop...
> >
> >
>
> huh?? What about max()? Granted, it's "only" the maximum, but
computers
> never find suprema...
>
> -s
>
> _______________________________________________
> Gretl-users mailing list
> Gretl-users(a)lists.wfu.edu
> http://lists.wfu.edu/mailman/listinfo/gretl-users
>