[Jack] you mean, something like this? <hansl> function series rankingalt(series x) matrix a = aggregate(const, x) return replace(x, a[,1], cum(0 | a[1:rows(a)-1,2])) end function </hansl> AP: To the extend I understand the code, I don't think so. I want a series that has the length of the sample, exactly as the "ranking" function gives. The only difference between the "ranking" function and the "rankingalt" function is that the "rankingalt" function <<Returns a series or vector with the ranks of y. The rank for observation i here is the number of elements that are less or equal than y_i.>> Namely we do not subtract half of ties, as we do in the "ranking" function. I didn't suggest to replace the ranking function, just asked if we could have also the "rankingalt" function. -- Alecos Papadopoulos PhD Athens University of Economics and Business web: alecospapadopoulos.wordpress.com/ cell:+30-6945-378680 skype:alecos.papadopoulos