1:18 p.m.
Hi,
there is this nice way to construct new series with the use of "...? ... :"
But this method seems not to work for matrices. The ".>" operator just
works 'on his own'.
<hansl>
nulldata 10
set optimizer bfgs
series test=normal()
matrix testm={test}
series ytest=test>0
matrix ytestm=testm.>0 *#this works*
series mtest = ytest ? 10 : 2
print ytest mtest -o
matrix mtestm = (ytestm.>0) ? 10 : 2 *#this works not*
eval mtestm
matrix mtestm=zeros(rows(ytestm),1)
loop for i=1..rows(ytestm) -q
matrix mtestm[i] = (ytestm[i]>0) ? 10 : 2
endloop
eval mtestm
<hansl>
Cheers
Leon
1:09 a.m.
On Sun, 4 Nov 2012, Pindar wrote:
matrix mtestm = (ytestm.>0) ? 10 : 2 #this works not
Yes, it is guaranteed by hansl syntax that it "works not".
The condition behind the "?" operator is not a boolean yes/no
condition, as it must be in context -- unless "ytestm" happens to be
the name of a 1 x 1 matrix. As I explained not so long ago on this
list, ".>0" is an element-wise operator which returns a matrix
result. And In hansl a matrix cannot serve as a boolean condition.
In principle one could interpret the above statement as "create a
matrix mtestm of the same dimensions as ytestm, such that element
(i,j) of mtestm is 10 or 2 as element (i,j) of ytestm is positive or
not" but at present hansl does not implement that sort of statement,
nor does it claim to.
Allin Cottrell
10:37 p.m.
On Sun, 4 Nov 2012, Allin Cottrell wrote:
On Sun, 4 Nov 2012, Pindar wrote:
> matrix mtestm = (ytestm.>0) ? 10 : 2 #this works not
Yes, it is guaranteed by hansl syntax that it "works not".
Second thoughts about this. We want to support as many uses of the
various operators in hansl as make good sense (in the context of a
variety of types). And I can see that your statement could make good
sense -- on condition that ytestm is an (m x n) matrix and that
mtestm should be a matrix of the same dimensions.
In gretl CVS we now support a matrix condition for the ternary "?"
operator. Here's an example that now works:
<hansl>
matrix M = I(3)
matrix A = M .> 0 ? 10 : -2
print A
</hansl>
which gives
? print A
A (3 x 3)
10 -2 -2
-2 10 -2
-2 -2 10
This is not yet in the snapshots for Windows and OS X, but it will
be before long.
Allin Cottrell
8:29 a.m.
Am 06.11.2012 23:37, schrieb Allin Cottrell:
On Sun, 4 Nov 2012, Allin Cottrell wrote:
> On Sun, 4 Nov 2012, Pindar wrote:
>
>> matrix mtestm = (ytestm.>0) ? 10 : 2 #this works not
> Yes, it is guaranteed by hansl syntax that it "works not".
Second thoughts about this. We want to support as many uses of the
various operators in hansl as make good sense (in the context of a
variety of types). And I can see that your statement could make good
sense -- on condition that ytestm is an (m x n) matrix and that
mtestm should be a matrix of the same dimensions.
In gretl CVS we now support a matrix condition for the ternary "?"
operator. Here's an example that now works:
Dear Allin,
hansl is the best scripting language I know, and now it's even better -
that's great!
I wanted to reproduce the advanced mle script in matrix form and that's
how I came across this statement.
Have a nice day
Leon
<hansl>
matrix M = I(3)
matrix A = M .> 0 ? 10 : -2
print A
</hansl>
which gives
? print A
A (3 x 3)
10 -2 -2
-2 10 -2
-2 -2 10
This is not yet in the snapshots for Windows and OS X, but it will
be before long.
Allin Cottrell
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