Re: [Gretl-users] Supremum (sup) of a time series

Ehm... Probably I have used extra (and non necessary) commands!!! but I got the result :) here is the code... i=1 scalar D= abs(IP[i,]) loop 60 if D < abs(IP[i+1,]) D = abs(IP[i+1,]) else D=D endif i=i+1 endloop so, you are saying that i can simply put D = max(abs(IP)) ?? im my data IP is saved as a matrix (60x1)... 2013/6/17 Sven Schreiber <svetosch(a)gmx.net&gt; > Am 17.06.2013 12:03, schrieb Gabriela Nodari: > > the supremum of a time series: Oh right, I got it with a simple loop... > > > > > > huh?? What about max()? Granted, it's "only" the maximum, but computers > never find suprema... > > -s > > _______________________________________________ > Gretl-users mailing list > Gretl-users(a)lists.wfu.edu > http://lists.wfu.edu/mailman/listinfo/gretl-users >