Dear Charles,
Thank you for your comments. As you state, it is not a-priori known which coefficients
would be significant. I wrote to Jack, that I tried to use an if-block to allow for this
problem, which unfortunately did not work. Anyway I would still be left with the problem
of how to create a matrix of dimension (T by n), where the coefficients of a regressor are
always in the same column.
If I use the structure below, then the script brakes down if I start with, say 2
significant regressors, and within the next time window there are three significant
regressors.
matrix CO3={}
.
.
.
matrix co = $coeff'
CO3 = CO3 | co
Kind regards,
Jan
Von: Plus.line MailSystem [mailto:cyrus@mailer.plusline.de] Im Auftrag von Charles Ward
Gesendet: Sonntag, 2. September 2012 17:24
An: Gretl list
Betreff: Re: [Gretl-users] data mining with rolling regression and restricted
coefficients
One trick to use for this type of problem is to transform the regression.
So if we want to regress y against x1, x2 and x3 and constrain the parameters to sum to 1
we do the following,
Subtract x1 from each of the other variables so we have y-x1, x2-x1, x3-x1
Regress y-x1 against the other two variables (no constraints needed unless you want all
the parameters to be positive).
y-x1 = A + B(x2-x1) + C(x3-x1) +e
Rearranging the results gives us
y = A + x1(1-B-C) + Bx2 + Cx3 +e
Thus the parameters sum to 1.
The only problem in your case is that it would be easier to program if you have one
variable (x1 in the above case) that is always present on the RHS of the regression.
Charles Ward
http://www.icmacentre.ac.uk/person/professor-charles-ward
On 29 August 2012 14:38, Jan Tille
<Jan.Tille@absolut-research.de<mailto:Jan.Tille@absolut-research.de>> wrote:
Dear gretl users,
first of all let me thank you, that you have already provided me with solutions on other
topics. Unfortunately, I need your help again.
The problem I am now trying to solve is the following.
Basically, I want to set up a rolling regression with parameter restrictions (all
parameters, except for the constant shall sum to one) and store the coefficient estimates.
So far this poses no problem:
<hansl>
Matrix C={}
List indep=indep1..indep10
Smpl 1 36
Loop i=1..360
Ols dep const indep
Restrict
b[2]+b[3]+b[4]+b[5]+ b[6]+b[7]+b[8]+b[9]+b[10]=1
end restrict
Matrix c=coeff'
C=C|c
Smpl +1 +1
Endloop
</hansl>
But as you can see, I have lots of regressors and not all might be significant, or
depending on the time window the significance will change.
I know that I can use the omit --auto function to select only significant coefficient
estimates, but here it is, where the problems start:
1.) Assume that during the first window, there are 3 significant coefficients, so that the
matrix will have 3 columns. If it should be, that during the next time window, there are,
say 4 significant coefficients, then the script breaks down (matrices do not fit).
Therefore, I guess I have to reshape the matrix somehow, to allow for the new column.
2.)Assume that during the first window there are 3 significant coefficients (2, 3, 4) and
during the next time window there are 3 different significant coefficients (6,7,8). Then,
the dimension of the matrix would be correct, but interpreting the matrix of coefficients
afterwards in a time series context would not make much sense.
To summarize 1.) and 2.), I would need a matrix with 10 columns, where "NA" is
entered, if the respective coefficient is insignificant and else the coefficient. So that
one can obtain the time series of significant regressors.
Date indep1 indep2 ... indep10
1 0,8 0,1 0,1
2 0,6 NA NA
3 0,75 NA 0,05
The third issue arises with the parameter restriction. After omitting insignificant
variables, the restriction that coefficients sum to one should still apply.
Unfortunately there seems to be no simple shortcut for the restriction (for example
restrict sum(coeff(2..n))) , whith n being the last significant coefficient).
As I don't know ex-ante which parameters would be significant, I somehow have to
dynamically readjust the restriction. Is there a way how one can do it?
Thanks in advance for your time answering my questions.
Kind regards,
Jan
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