Re: [Gretl-users] error: read out varname using loop
On Fri, 16 Jan 2015, Artur T. wrote:
Thank you for the quick reply, Allin. I totally missed this -- but
good
to know.
An alternative I have used is:
<hansl>
list X = LRM LRY
lname = strsub(varname(X),","," ")
loop i=1..2 -q
string vname = strsplit(lname,$i)
print vname
endloop
</hansl>
Hmm, reminder to self: we really ought to provide a way to get an
array of strings back from varname() as applied to a list! That would
enable a cleaner version of what you're doing above.
Allin