On Thu, 15 Nov 2012, Pindar wrote:
And in terms of 'the loop line' string-substitution generates
also an error:
(my challenge solution of the interaction stuff)
True, up till now $-string substitution has not been available
in the line that starts a loop. This is now relaxed. In
current CVS both of the following should work OK, regardless
of the language in which gretl is running:
<hansl>
# Using numerical values
loop i=1..4 -q
printf "i=%d\n", i
loop j=i+1..i+2 -q
printf " j=%d\n", j
endloop
endloop
# Using string substitution
loop i=1..4 -q
printf "i=$i\n"
loop j=$i+1..$i+2 -q
printf " j=$j\n"
endloop
endloop
</hansl>
Allin Cottrell