[Gretl-users] Re: if condition: evaluating NA values
....
Python does not throw an error and returns "1"
<python>
import math
foo = math.nan
actual = 0
if foo:
actual += 1
print(actual)
</python>
So, two of the three languages I used throw an error. Python is known
for its rather "sloppy" handling of types :-D
....
Python has the "everything is an object, except None" rule. You are not
testing for boolean but the existence of objects.
foo = None
if foo:
print("foo exists")
import math
bar = math.nan
if bar:
print("bar exists")
>>bar exists
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