[Gretl-users] Re: Gretl-users Digest, Vol 147, Issue 30 (series from matrix)
Thanks Artur I think this is it. I found out that for some reason the
first-to-be-generated vector "q" in my script below had lower dimension
than the sample size. I don't know why that happened yet. But when I
managed to obtain a "q" vector with the correct dimension, then the line
<<series qqq = sumr(q.*qq)>>
worked just fine, and gave me qqq as a series.
Thanks!
Alecos Papadopoulos PhD
Athens University of Economics and Business
web: alecospapadopoulos.wordpress.com/
cell:+30-6945-378680
skype:alecos.papadopoulos
On 27/4/2019 01:00, gretl-users-request(a)gretlml.univpm.it wrote:
Date: Fri, 26 Apr 2019 21:09:27 +0200 From: Artur Tarassow
<atecon(a)posteo.de> Subject: [Gretl-users] Re: Series from matrix To:
gretl-users(a)gretlml.univpm.it Message-ID:
<44aa51da-ae2c-5bdb-4362-3c61fad929f3(a)posteo.de> Content-Type:
text/plain; charset=iso-8859-7; format=flowed Am 26.04.19 um 21:06
schrieb Alecos Papadopoulos:
> Good afternoon.
>
> Has something changed in Gretl related to how we get data out of a
> matrix column and into a series?
>
> I had an old mle script that included
>
> series qqq = sumr(q.*qq)
>
> where the right hand side is a column vector. It had worked in the
> past, but it doesn't appear to work any more, I get
>
> <<Incompatible types in assignment: series = matrix . The formula
> 'series qqq = sumr(q.*qq)' produced an error on execution>>
Hi Alecos,
I've experienced some similar behaviour a while ago. Could you check
please that the length of the resulting vector exactly meets the length
of the currently selected data set?
Artur
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