Am 09.06.2016 um 17:36 schrieb Riccardo (Jack) Lucchetti:
On Thu, 9 Jun 2016, Sven Schreiber wrote:
> I want to check a series for ties, meaning exact values that
> more than once in the series, and also get the respective counts of
> how many occurrences there are at each of these ties.
so you basically want a frequency distribution, right?
Yes I guess so.
How do you like this?
x = floor(uniform()*4)
X = aggregate(const, x)
So apparently the third argument of 'aggregate()' is optional? It isn't
mentioned in the docs, it's interesting to know.