Am 21.06.2013 11:08, schrieb Artur Tarassow: > Hello, > > I just noticed that I cant use an arbitrary positive scalar as the third > argument in the seq function. > This does not work: > matrix sq = seq(0.1,40.2,0.1) > > whereas this works: > matrix sq = seq(0.1,40.2,1) > sq > > Is there a reason for this limitation? For instance, Gauss' seqa > function accepts any positive scalar. > I'm not sure what the original reason was, and I can see both pro and contra arguments. In any case it's quite easy to achieve what you want; let's call your increment 1/x with x>1, then do: seq(a*x,b*x)/x In your example: seq(1,402)/10 -sven _______________________________________________ Gretl-users mailing list Gretl-users(a)lists.wfu.edu http://lists.wfu.edu/mailman/listinfo/gretl-users