1:46 p.m.
Dear Gretl Community,
I need to retrieve a name of a specific element from a list and use it as a
string. I tried the following commands:
<hansl code>
open australia.gdt
list L = PAU PUS E
string S = varname(varnum(L[2]))
</hansl code>
Best,
Henrique Andrade
2:29 p.m.
Henrique,
Try this
function strings varnames(list in)
#Returns an array of strings containing the names of each variable in a list
catch strings ret = strsplit(strsub(varname(in),","," "))
if $error != 0
strings ret
string errormesage = errmsg($error)
print errormesage
endif
return ret
end function
This function returns the names of the variables as an array of strings.
Logan
From: gretl-users-bounces(a)lists.wfu.edu [mailto:gretl-users-bounces@lists.wfu.edu] On
Behalf Of Henrique Andrade
Sent: Thursday, February 05, 2015 7:47 AM
To: Gretl Discussion List (users)
Subject: [Gretl-users] How to retrieve a list's element name
Dear Gretl Community,
I need to retrieve a name of a specific element from a list and use it as a string. I
tried the following commands:
<hansl code>
open australia.gdt
list L = PAU PUS E
string S = varname(varnum(L[2]))
</hansl code>
Best,
Henrique Andrade
2:32 p.m.
Please, see the solution given by Allin some time ago:
http://lists.wfu.edu/pipermail/gretl-users/2012-August/007836.html
On 05/02/15 14:46, Henrique Andrade wrote:
Dear Gretl Community,
I need to retrieve a name of a specific element from a list and use it
as a string. I tried the following commands:
<hansl code>
open australia.gdt
list L = PAU PUS E
string S = varname(varnum(L[2]))
</hansl code>
Best,
Henrique Andrade*
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2:54 p.m.
Dear Logan, Allin and Ignacio,
Thanks a lot for your help. For simplicity reasons I used the solution
proposed by Allin.
But I would like to report a little strange behavior. The following command
gives different results when executed in different Gretl's builds:
<hansl code>
open australia.gdt
list L = PAU PUS E
eval L[2]
</hansl code>
Output:
Gretl 1.10.0cvs (build 2015-02-04)
? list L = PAU PUS E
? eval L[2]
PUS
Gretl 1.10.0cvs (build 2014-12-31)
? list L = PAU PUS E
? eval L[2]
2
Because of this my code worked just fine with Gretl 1.10.0cvs (build
2014-12-31).
Best,
Henrique Andrade
2:33 p.m.
On Thu, 5 Feb 2015, Henrique Andrade wrote:
Dear Gretl Community,
I need to retrieve a name of a specific element from a list and use it as a
string. I tried the following commands:
<hansl code>
open australia.gdt
list L = PAU PUS E
string S = varname(varnum(L[2]))
</hansl code>
As an argument for varname(), you need the numerical value of
the given element of L (the series index number). You can get that by
turning L into a matrix (in effect, a vector of integers):
matrix m = L
string S = varname(m[2])
Allin Cottrell
3609
days inactive
3609
days old
4 comments
4 participants
participants (4)
-
Allin Cottrell -
Henrique Andrade -
Ignacio Diaz-Emparanza -
Logan Kelly