Re: [Gretl-users] foreach vs for with list

Hi there, I'd expect both options to be equivalent (add a matrix with the data from the series to the array of matrices). However, the forach loop only adds the first data-point to the matrix. <hansl> open denmark.gdt -q list ls = 1 4 matrices M = null loop foreach l ls matrix temp = l colnames(temp,varname(l)) M+=temp endloop matrices M2 = null loop s=1..nelem(ls) matrix temp = ls[s] colnames(temp,varname(ls[s])) M2 += temp endloop ?M ?M2 </hansl> produces: <output> ? M Array of matrices, length 2 [1] 1 x 1 [2] 1 x 1 ? M2 Array of matrices, length 2 [1] 55 x 1 [2] 55 x 1 <\output> > -----Ursprüngliche Nachricht----- > Von: gretl-users-bounces(a)lists.wfu.edu [mailto:gretl-users- > bounces(a)lists.wfu.edu] Im Auftrag von Sven Schreiber > Gesendet: Freitag, 15. Dezember 2017 17:55 > An: gretl-users(a)lists.wfu.edu > Betreff: Re: [Gretl-users] foreach vs for with list > > Am 15.12.2017 um 17:49 schrieb Schaff, Frederik: > > > why are those not equivalent? I.e., the foreach (which is more > > concise) does not work as (I) expected. > > > >     loop for s=1..nelem(ls) > > BTW, this syntax is not optimal (even though it's tolerated) -- for the simplest > index loop omit the "for": loop s=1..nelem(ls) will do. > > cheers, > sven > _______________________________________________ > Gretl-users mailing list > Gretl-users(a)lists.wfu.edu > http://lists.wfu.edu/mailman/listinfo/gretl-users