Re: [Gretl-users] string substitution with sprintf?

-----Original Message----- From: gretl-users-bounces(a)lists.wfu.edu [mailto:gretl-users- bounces(a)lists.wfu.edu] On Behalf Of Allin Cottrell Sent: Tuesday, April 12, 2016 8:33 PM To: Gretl list Subject: Re: [Gretl-users] string substitution with sprintf? On Tue, 12 Apr 2016, Summers, Peter wrote: > Hi all, > > I'm trying to write a script that will produce a LaTeX table as output - basically a customized version of tabprint. Here's the basic idea: > <hansl> > matrix doh = mnormal(1,3) # this would be a coefficient vector, e.g. > > string fmt = "%.4g " > string baz = "doh[1]" > loop i=2..cols(doh) # build up the format and argument strings > fmt ~= " & %.4g " > baz ~= ", doh[$i]" > endloop > fmt > baz > > sprintf Foo "\"%s\"\n", fmt > Foo > > # this printf is what I want, but I want to use the "fmt" string above > printf "%.4g & %.4g & %.4g\n", @baz > > # this seems like it should work, but I get a "syntax error" > sprintf bar Foo, @baz > </hansl> I guess it's time to replace the doc for the "sprintf" command with a "deprecated" statement plus pointer to the sprintf() function, which is now the recommended form. <hansl> matrix doh = mnormal(1,3) string fmt = "%.4g " string args = "doh[1]" loop i=2..cols(doh) -q fmt ~= " & %.4g " args ~= ", doh[$i]" endloop # assuming you want a terminating newline fmt ~= "\n" Foo = sprintf(fmt, @args) Foo </hansl> We recommend, these days, that string substitution be kept to a minimum, but the "args" argument requires it in context, so OK. Allin _______________________________________________ Gretl-users mailing list Gretl-users(a)lists.wfu.edu http://lists.wfu.edu/mailman/listinfo/gretl-users