Re: [Gretl-users] seq function
Am 21.06.2013 11:08, schrieb Artur Tarassow:
Hello,
I just noticed that I cant use an arbitrary positive scalar as the third
argument in the seq function.
This does not work:
matrix sq = seq(0.1,40.2,0.1)
whereas this works:
matrix sq = seq(0.1,40.2,1)
sq
Is there a reason for this limitation? For instance, Gauss' seqa
function accepts any positive scalar.
I'm not sure what the original reason was, and I can see both pro and
contra arguments.
In any case it's quite easy to achieve what you want; let's call your
increment 1/x with x>1, then do:
seq(a*x,b*x)/x
In your example: seq(1,402)/10
-sven