Dear Gretl Community, I'm trying to use a loop index inside a script but I don't know how. According to "Gretl User’s Guide" the syntax looks like this: loop i=1..24 But I just need the points where "i" is equal to 6, 12 and 24. Something like this: loop i=6;12;24 How can I do that?

Or, if your index is something like of a geometric series as it seems to be (let's say 6, 12, 24, 48, and so on) and too long to do manually you can try this one: <script> scalar count=0 loop for (count=6;count<=24;count=count*2) --quiet <instructions> endloop <\script> cheers, artur Riccardo (Jack) Lucchetti a écrit : > On Tue, 25 May 2010, Henrique Andrade wrote: > >> Dear Gretl Community, >> >> I'm trying to use a loop index inside a script but I don't know how. >> According >> to "Gretl User’s Guide" the syntax looks like this: >> >> loop i=1..24 >> >> But I just need the points where "i" is equal to 6, 12 and 24. >> Something like this: >> >> loop i=6;12;24 >> >> How can I do that? > > For example, this way: > <script> > matrix foo = { 6, 12, 24 } > n = cols(foo) > loop for i=1..n > bar = foo[i] > print bar > end loop > </script> > > > Riccardo (Jack) Lucchetti > Dipartimento di Economia > Università Politecnica delle Marche > > r.lucchetti(a)univpm.it > http://www.econ.univpm.it/lucchetti > ------------------------------------------------------------------------ > > _______________________________________________ > Gretl-users mailing list > Gretl-users(a)lists.wfu.edu > http://lists.wfu.edu/mailman/listinfo/gretl-users _______________________________________________ Gretl-users mailing list Gretl-users(a)lists.wfu.edu http://lists.wfu.edu/mailman/listinfo/gretl-users

wrote:

Dear Riccardo, Kehl and Artur, Thanks a lot for your help! I'd tried all the options you gave me and my final script looks like this: <script> scalar n=0 loop for (n=6;n<=24;n=n*2) --quiet scalar m = $T - n + 1 loop j=2..nelemY --quiet matrix R$n_$j = zeros(m,1) loop i=1..m --quiet loop c=1..n --quiet row = i + n - c R$n_$j[i] += r$j[row, c] endloop endloop endloop matrix mci$n = R$n_2 + R$n_3 endloop </script> Now, because I just need the values for 6, 12 and 24, I'm trying to substitute the second line "loop for (n=6;n<=24;n=n*2)" for this: loop for (n=6;n=12;n=24) But the script isn't working. Any hints? Best regards, Henrique 2010/5/25 artur bala <artur.bala(a)laposte.net&gt; Or, if your index is something like of a geometric series as it seems to > be (let's say 6, 12, 24, 48, and so on) and too long to do manually > you can try this one: > <script> > scalar count=0 > loop for (count=6;count<=24;count=count*2) --quiet > <instructions> > endloop > <\script> > > cheers, > artur > > Riccardo (Jack) Lucchetti a écrit : > > On Tue, 25 May 2010, Henrique Andrade wrote: > > > >> Dear Gretl Community, > >> > >> I'm trying to use a loop index inside a script but I don't know how. > >> According > >> to "Gretl User’s Guide" the syntax looks like this: > >> > >> loop i=1..24 > >> > >> But I just need the points where "i" is equal to 6, 12 and 24. > >> Something like this: > >> > >> loop i=6;12;24 > >> > >> How can I do that? > > > > For example, this way: > > <script> > > matrix foo = { 6, 12, 24 } > > n = cols(foo) > > loop for i=1..n > > bar = foo[i] > > print bar > > end loop > > </script> > > > > > > Riccardo (Jack) Lucchetti > > Dipartimento di Economia > > Università Politecnica delle Marche > > > > r.lucchetti(a)univpm.it > > http://www.econ.univpm.it/lucchetti > > ------------------------------------------------------------------------ > > > > _______________________________________________ > > Gretl-users mailing list > > Gretl-users(a)lists.wfu.edu > > http://lists.wfu.edu/mailman/listinfo/gretl-users > > > _______________________________________________ > Gretl-users mailing list > Gretl-users(a)lists.wfu.edu > http://lists.wfu.edu/mailman/listinfo/gretl-users > -- Henrique C. de Andrade Doutorando em Economia Aplicada Universidade Federal do Rio Grande do Sul www.ufrgs.br/ppge _______________________________________________ Gretl-users mailing list Gretl-users(a)lists.wfu.edu http://lists.wfu.edu/mailman/listinfo/gretl-users

Dear Riccardo, Kehl and Guilherme, I was looking for something simple. The option "loop for (n=6; n<=24; n*=2)" worked just fine. But in my humble opinion the option "loop for (n=6; n=12; n=24)" should work too, but this is not a big deal ;-) Thank you so much! Um abraço, Henrique Em 25 de maio de 2010 17:45, Hélio Guilherme <helioxentric(a)gmail.com&gt;escreveu: Hi Henrique, > > I believe that this does what you want: > loop for (n=6; n<=24; n*=2) --quiet > > No other simple options. > > > On Tue, May 25, 2010 at 8:53 PM, Henrique Andrade < > henrique.coelho(a)gmail.com&gt; wrote: > >> Dear Riccardo, Kehl and Artur, >> >> Thanks a lot for your help! I'd tried all the options you gave me and >> my final script looks like this: >> >> <script> >> scalar n=0 >> loop for (n=6;n<=24;n=n*2) --quiet >> scalar m = $T - n + 1 >> loop j=2..nelemY --quiet >> matrix R$n_$j = zeros(m,1) >> loop i=1..m --quiet >> loop c=1..n --quiet >> row = i + n - c >> R$n_$j[i] += r$j[row, c] >> endloop >> endloop >> endloop >> matrix mci$n = R$n_2 + R$n_3 >> endloop >> </script> >> >> Now, because I just need the values for 6, 12 and 24, I'm trying to >> substitute the second line "loop for (n=6;n<=24;n=n*2)" for this: >> >> loop for (n=6;n=12;n=24) >> >> But the script isn't working. Any hints? >> >> Best regards, >> Henrique >> >> >> 2010/5/25 artur bala <artur.bala(a)laposte.net&gt; >> >> Or, if your index is something like of a geometric series as it seems to >>> be (let's say 6, 12, 24, 48, and so on) and too long to do manually >>> you can try this one: >>> <script> >>> scalar count=0 >>> loop for (count=6;count<=24;count=count*2) --quiet >>> <instructions> >>> endloop >>> <\script> >>> >>> cheers, >>> artur >>> >>> Riccardo (Jack) Lucchetti a écrit : >>> > On Tue, 25 May 2010, Henrique Andrade wrote: >>> > >>> >> Dear Gretl Community, >>> >> >>> >> I'm trying to use a loop index inside a script but I don't know how. >>> >> According >>> >> to "Gretl User’s Guide" the syntax looks like this: >>> >> >>> >> loop i=1..24 >>> >> >>> >> But I just need the points where "i" is equal to 6, 12 and 24. >>> >> Something like this: >>> >> >>> >> loop i=6;12;24 >>> >> >>> >> How can I do that? >>> > >>> > For example, this way: >>> > <script> >>> > matrix foo = { 6, 12, 24 } >>> > n = cols(foo) >>> > loop for i=1..n >>> > bar = foo[i] >>> > print bar >>> > end loop >>> > </script> >>> > >>> > >>> > Riccardo (Jack) Lucchetti >>> > Dipartimento di Economia >>> > Università Politecnica delle Marche >>> > >>> > r.lucchetti(a)univpm.it >>> > http://www.econ.univpm.it/lucchetti >>> > >>> ------------------------------------------------------------------------ >>> > >>> > _______________________________________________ >>> > Gretl-users mailing list >>> > Gretl-users(a)lists.wfu.edu >>> > http://lists.wfu.edu/mailman/listinfo/gretl-users >>> >>> >>> _______________________________________________ >>> Gretl-users mailing list >>> Gretl-users(a)lists.wfu.edu >>> http://lists.wfu.edu/mailman/listinfo/gretl-users >>> >> >> >> >> -- >> Henrique C. de Andrade >> Doutorando em Economia Aplicada >> Universidade Federal do Rio Grande do Sul >> www.ufrgs.br/ppge >> >> _______________________________________________ >> Gretl-users mailing list >> Gretl-users(a)lists.wfu.edu >> http://lists.wfu.edu/mailman/listinfo/gretl-users >> > > > _______________________________________________ > Gretl-users mailing list > Gretl-users(a)lists.wfu.edu > http://lists.wfu.edu/mailman/listinfo/gretl-users > -- Henrique C. de Andrade Doutorando em Economia Aplicada Universidade Federal do Rio Grande do Sul www.ufrgs.br/ppge _______________________________________________ Gretl-users mailing list Gretl-users(a)lists.wfu.edu http://lists.wfu.edu/mailman/listinfo/gretl-users

Dear Riccardo, Kehl and Guilherme, I was looking for something simple. The option "loop for (n=6; n<=24; n*=2)" worked just fine. But in my humble opinion the option "loop for (n=6; n=12; n=24)" should work too, but this is not a big deal ;-)