Re: [Gretl-devel] NA not recognized by isnan()
Am 25.11.2014 um 15:59 schrieb Allin Cottrell:
On Tue, 25 Nov 2014, Sven Schreiber wrote:
> this is weird:
>
> <hansl>
> s0 = NA
> print s0
> a = isnan(s0) # gives 0!?
> </hansl>
s0 is NA, it's not NaN.
ah, right -- after a long-ago discussion about NA and NaN I had sort of
made a note to myself that gretl doesn't really distinguish between the
two, but obviously that wasn't the whole truth. Plain old missing(s0)
works fine here.
thanks,
sven