Am 06.05.2021 um 07:42 schrieb atecon:
Hi all,
I just would like to ask whether this behavior is actually expected:
<hansl>
matrix m = {1, NA; 2, 3}
print m
eval cum(m)
? print m
m (2 x 2)
1 nan
2 3
? eval cum(m)
1 nan
3 nan
</hansl>
I expected the entry (2,2) to be 3 as this is the first valid value of
the 2nd column.
I'd say it's expected because nans propagate. Basically you don't know
what 3 + nan is. To get what you want, I was going to say "do
cum(misszero(m))", but that doesn't work on a matrix. Maybe it should?
(But remember the old fact that a NaN and a missing value is not always
the same thing.)
cheers
sven