Hi,
I'm wondering what the value added of 'inbundle' over 'exists' is. In
principle both check for the existence of an object and return a type
code if yes.
I know that currently where inbundle(b, "m") returns 0 because m isn't
there, exists(b.m) instead yields an error. But I guess that could be
changed if wanted.
And vice versa: inbundle(a, "x") yields an error if there is no bundle
a, whereas exists(a.x) just returns 0. But are those differences really
by design or just by historical coincidence?
thanks
sven