It looks like the tokenizer
ignores brackets!
(10^-5)^2 outputs the same as
10^-5^2
Oleh
7 квітня 2016, 17:23:45, від oleg_komashko(a)ukr.net:
Dear all,
It seems to be a non-standard
precedence:
(10^-5)^2 is evaluated as 10^((-5)^2)
Oleh
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