Am 03.03.2015 um 18:59 schrieb Ignacio Diaz-Emparanza:
On 03/03/15 17:31, Sven Schreiber wrote:
> If I'm not mistaken these Portmanteau type of tests do not
only
> require large T but also large m (max lag considered).
In most practical cases no, I think this is not true. m has to be large
enough to have a sense (including the relevant correlations) but not
very large because this may imply very low power.
Yes I know, but I was talking about the asymptotic argument.
> So the whole business becomes even murkier when m is so small that
> m-p-q becomes negative. Also using dof=m instead of m-p-q is not wrong
> asymptotically I believe, it's all "just" about small-sample
> corrections (which can be very important of course though).
If your T is very very large you may calculate the Q stat for a very
large m, and then given p and q not very large, a chi-square(m) and
chi-square (m-p-q) may be similar. But usually we don't have so large T
and we are interested in relatively low values of m. From m>p+q we have
enough dof and the Q stat for a residuals series may have sense, and
the asymptotic distribution is chi-square (m-p-q) different from the
chi-square(m).
I'm tempted to dive into the details, but not now; let me just say that
this whole discussion has not weakened my skepticism about using the
Q-type tests for residuals (as opposed to raw original series).
thanks,
sven