12:07 p.m.
Dear all,
I want to get rid of the "time" variable from a list. This works fine
out of a function but not within a function:
<hansl>
open denmark.gdt -q
list y = const time
# WORKS
y -= const
y
y -= time
y # list is null
# DOESN'T WORK
function void foo (list y)
y -= const
y
y -= time
y # time is still in the list
end function
foo(y)
I am using the current git version on ubuntu.
Best,
Artur
2:20 p.m.
Am 01.12.2016 um 13:07 schrieb Artur T.:
I want to get rid of the "time" variable from a list. This works fine
out of a function but not within a function:
y -= time
Inside a function you have to specify the list from which the series is
supposed to come. 'time' is no exception here:
y -= y.time
will work (have just tested it).
The exception is rather 'const', because your expression
y -= const
works although it's not given like 'y.const'. I guess the reason is that
const has special properties, always being present in the dataset,
having index 0 etc.
cheers,
sven
2:52 p.m.
Thanks, Sven, I forgot about this dot in y.time!
Best,
Artur
Am 01.12.2016 um 15:20 schrieb Sven Schreiber:
Am 01.12.2016 um 13:07 schrieb Artur T.:
>
> I want to get rid of the "time" variable from a list. This works fine
> out of a function but not within a function:
> y -= time
Inside a function you have to specify the list from which the series is
supposed to come. 'time' is no exception here:
y -= y.time
will work (have just tested it).
The exception is rather 'const', because your expression
y -= const
works although it's not given like 'y.const'. I guess the reason is that
const has special properties, always being present in the dataset,
having index 0 etc.
cheers,
sven
11:07 a.m.
Let me come back to yesterdays issue. I am trying to run the following
check whether variable "time" is in the list rxlist, or not. When time
is not part of the list, I obtain the error message "error evaluating
'if'". However, I think gretl should simply return a zero in this case.
Artur
<hansl>
function bundle foo (const list rxlist[null] "List of addit. regressors")
bundle b
rxlist
if !inlist(rxlist, rxlist.time)
printf "No time trend in rxlist!\n"
endif
if inlist(rxlist,rxlist.time)
rxlist -= rxlist.time
endif
rxlist
return b
end function
open denmark.gdt -q
genr time
# Case 1: const + time
list rxlist = const time
foo(rxlist)
# Case 2: const
list rxlist = const
foo(rxlist)
</hansl>
Am 01.12.2016 um 15:20 schrieb Sven Schreiber:
Am 01.12.2016 um 13:07 schrieb Artur T.:
>
> I want to get rid of the "time" variable from a list. This works fine
> out of a function but not within a function:
> y -= time
Inside a function you have to specify the list from which the series is
supposed to come. 'time' is no exception here:
y -= y.time
will work (have just tested it).
The exception is rather 'const', because your expression
y -= const
works although it's not given like 'y.const'. I guess the reason is that
const has special properties, always being present in the dataset,
having index 0 etc.
cheers,
sven
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2:18 p.m.
Am 02.12.2016 um 12:07 schrieb Artur T.:
Let me come back to yesterdays issue. I am trying to run the
following
check whether variable "time" is in the list rxlist, or not. When time
is not part of the list, I obtain the error message "error evaluating
'if'". However, I think gretl should simply return a zero in this case.
Yes it seems 'inlist()' has some problems. For example also 'eval
inlist(a, "s")' works (for 'a' as a defined list), although
according to
the doc a string as second argument wouldn't be allowed (should be an
identifier or an ID number).
The whole thing doesn't seem to be limited to "time", it's rather a
general issue about inlist() in functions -- the 'a.s' notation works in
one case but not in the other, and vice versa for the 's' notation.
Slightly OT: What are you trying to do, Artur? As a workaround you could
perhaps use:
if strstr(varname(rxlist), "time") != ""
(untested).
cheers,
sven
3:04 p.m.
Yes it seems 'inlist()' has some problems. For example also
'eval
inlist(a, "s")' works (for 'a' as a defined list), although
according to
the doc a string as second argument wouldn't be allowed (should be an
identifier or an ID number).
The whole thing doesn't seem to be limited to "time", it's rather a
general issue about inlist() in functions -- the 'a.s' notation works in
one case but not in the other, and vice versa for the 's' notation.
And I already thought I am too stupid to use the inlist() function
properly... ;-)
Slightly OT: What are you trying to do, Artur? As a workaround you
could
perhaps use:
if strstr(varname(rxlist), "time") != ""
(untested).
This works fine, Sven. Thanks. I totally forgot about this
construction.
Artur
7:42 p.m.
On Fri, 2 Dec 2016, Sven Schreiber wrote:
Am 02.12.2016 um 12:07 schrieb Artur T.:
> Let me come back to yesterdays issue. I am trying to run the following
> check whether variable "time" is in the list rxlist, or not. When time
> is not part of the list, I obtain the error message "error evaluating
> 'if'". However, I think gretl should simply return a zero in this case.
Yes it seems 'inlist()' has some problems. For example also 'eval inlist(a,
"s")' works (for 'a' as a defined list), although according to the
doc a
string as second argument wouldn't be allowed (should be an identifier or an
ID number).
The doc for inlist should be improved/updated, yes. But I think the
logic is correct (at least, arguably so).
If you'll permit me a silly analogy, consider these two questions:
Is Mr Frogbladder a member of parliament?
Is there a member of parliament named Mr Frogbladder?
The first version presupposes that a Mr Frogbladder exists in the
relevant context of discourse, while the second version does not. So
the first invites a response of "Ill-posed question" if there's no
Mr Frogbladder, while the second unambiguously gets an answer of No
in that case.
So now consider the following (where I've inverted the order to push
the error to the end):
<hansl>
nulldata 5
list L = const
eval inlist(L, const)
eval inlist(L, "frogbladder")
nulldata 5
list L = const
eval inlist(L, const)
eval inlist(L, frogbladder)
</hansl>
The answers are, respectively, 1, 0, 1 and <error> ("The symbol
'frogbladder' is undefined"). By putting the (putative) series-name
in quotes we're effectively asking the second of the original two
questions.
Artur's original question,
inlist(rxlist, rxlist.time)
is, it seems to me analogous to "Is Mr Frogbladder MP a member of
parliament?" (That is, is such-and-such a member of the list a
member of the list?) And it seems to me defensible that the question
fails. The right question is:
inlist(rxlist, "time")
As Sven remarked, this works but is not documented. I'll update the
doc.
Allin
2946
days inactive
2947
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6 comments
3 participants
participants (3)
-
Allin Cottrell -
Artur T. -
Sven Schreiber