On Wed, 24 Jan 2018, Sven Schreiber wrote: It may be funny (the message could be improved), but it's right! You cannot apply the '&' operator to bundle members (BMEMB) as such. If you want a function to be able to modify a bundle member you need to pass a pointer to the bundle itself. Allin

the same msg is put forward in the brief example I put under "Older discussion at gretl..." this week <hansl> nulldata 100 series A = normal() list L = A bundle boo bundle coo boo.coo = coo eval inbundle(boo,coo) boo.coo.L = L eval inbundle(boo.coo,L) function void testA(bundle Bndl) eval inbundle(Bndl,L) #eval argname(Bndl.L[1]) #error eval varname(Bndl.L[1]) #OK end function function void testB(bundle *Bndl) eval inbundle(Bndl,L) #not OK end function testA(boo.coo) #OK testB(&boo.coo) #not OK </hansl>