I've noticed that 'feval' always requires the explicit passing of an
argument to the specified function, as in 'feval("myfunc", 1)'. So the
following trivial example fails:
function scalar myfunc(int in)
result = feval("myfunc") # intended use: default args
Certainly no big deal, but wouldn't that be a valid use of the 'feval'
apparatus? BTW, the current behavior is implicitly documented alright
("one or more further args needed").
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