Hi, I've noticed that 'feval' always requires the explicit passing of an argument to the specified function, as in 'feval("myfunc", 1)'. So the following trivial example fails: <hansl> function scalar myfunc(int in[1]) return in end function result = feval("myfunc") # intended use: default args </hansl> Certainly no big deal, but wouldn't that be a valid use of the 'feval' apparatus? BTW, the current behavior is implicitly documented alright ("one or more further args needed"). thanks sven