Hi,
I've noticed that 'feval' always requires the explicit passing of an
argument to the specified function, as in 'feval("myfunc", 1)'. So the
following trivial example fails:
<hansl>
function scalar myfunc(int in[1])
return in
end function
result = feval("myfunc") # intended use: default args
</hansl>
Certainly no big deal, but wouldn't that be a valid use of the 'feval'
apparatus? BTW, the current behavior is implicitly documented alright
("one or more further args needed").
thanks
sven